0=1.1t^2-9.5t

Solution for 0=1.1t^2-9.5t equation:

0=1.1t^2-9.5t

We move all terms to the left:

0-(1.1t^2-9.5t)=0

We add all the numbers together, and all the variables

-(1.1t^2-9.5t)=0

We get rid of parentheses

-1.1t^2+9.5t=0

a = -1.1; b = 9.5; c = 0;
Δ = b2-4ac
Δ = 9.52-4·(-1.1)·0
Δ = 90.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.5)-\sqrt{90.25}}{2*-1.1}=\frac{-9.5-\sqrt{90.25}}{-2.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.5)+\sqrt{90.25}}{2*-1.1}=\frac{-9.5+\sqrt{90.25}}{-2.2}
$